Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Python Collections (2016, retired 2019) Dictionaries Word Count

Posted by Justin Mazenko
Justin Mazenko
6,768 Points

Error

I know I have the right answer, but the website keeps rejecting my solution; I think the problem is broken

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(string):
    lower_string = string.lower()
    word_list = lower_string.split(" ")
    word_dict = {}
    count = 0
    for word in word_list:
        if word not in word_dict.keys():
            count = word_list.count(word)
            word_dict[word] = count

1 Answer

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

Perhaps it's not quite as "right" as you thought. :wink:

At first glace, I notice two issues:

  • the instructions say "The function needs to return a dictionary", but nothing is being returned
  • the input is being split on explicit spaces instead of all whitespace