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![Tor Håkon Thomassen](https://secure.gravatar.com/avatar/ce4116c7b4eea6d51f4bd87efcea160f?s=96&d=https%3A%2F%2Fecs-static.teamtreehouse.com%2Fassets%2Fcontent%2Fdefault_avatar-445fbbabfc8dc9188fb5967fe43322ee0c3e0dd1e10f378bf8343784af5a13eb.webp&r=pg)
Tor Håkon Thomassen
669 PointsERROR
I tried expanding my code a little bit, and when I added the bottom step, I get the error.
I hope it's obvious what I tried doing here.
A. Why does the program think it's a unary operator I'm typing in? B. What can I do to fix this?
This is my code.
var range = 7;
if range > 5 && range < 20{
print("\(range) is pretty close");
} else if range > 20 {
print("\(range) is far away");
} else if range > 1 && < 4 { // ERROR: "<" is not a unary operator.
print("\(range) is far away");
}
MODERATOR EDIT adjusted markdown for Swift syntax
1 Answer
![Jason Anders](https://uploads.teamtreehouse.com/production/profile-photos/3512822/micro_Jason_s-Pic.jpg)
Jason Anders
Treehouse Moderator 145,859 PointsHey Tor,
You're on the right track. You are just missing the second reference to the variable being tested.
else if range > 1 && range < 4 //added second 'range'
See if that solves the issue. :)
Tor Håkon Thomassen
669 PointsTor Håkon Thomassen
669 PointsOf course! Thank you so much! It's been driving me crazy!