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iOS Swift Basics (retired) Control Flow Comparison and Logical Operators

Tor Håkon Thomassen
Tor Håkon Thomassen
669 Points
Posted by Tor Håkon Thomassen
Tor Håkon Thomassen
669 Points

ERROR

I tried expanding my code a little bit, and when I added the bottom step, I get the error.

I hope it's obvious what I tried doing here.

A. Why does the program think it's a unary operator I'm typing in? B. What can I do to fix this?

This is my code.

var range = 7;

if range > 5 && range < 20{
    print("\(range) is pretty close");
} else if range > 20 {
    print("\(range) is far away");
}  else if range > 1 && < 4 { // ERROR: "<" is not a unary operator.
    print("\(range) is far away");
}

MODERATOR EDIT adjusted markdown for Swift syntax

1 Answer

Jason Anders
MOD
Jason Anders
Treehouse Moderator 145,858 Points
Jason Anders
Jason Anders
Treehouse Moderator 145,858 Points

Hey Tor,

You're on the right track. You are just missing the second reference to the variable being tested.

else if range > 1 && range < 4 //added second 'range'

See if that solves the issue. :)

Tor Håkon Thomassen
Tor Håkon Thomassen
669 Points
Tor Håkon Thomassen
Tor Håkon Thomassen
669 Points

Of course! Thank you so much! It's been driving me crazy!