Error: "Didn´t get the right output. Output was ['123456', Treehouse', student', 'Kenneth', 'Python']. Length was 6."

Question

In this exercise my idea was to find everything that is not a space. Later I created a new list with the words to do a filter after that with if statement.

Any clue of what I'm doing wrong would be apreciated Thanks!!!

word_length.py

import re

# EXAMPLE:
# >>> find_words(4, "dog, cat, baby, balloon, me")
# ['baby', 'balloon']


def find_words(n, s):
    a = re.findall(r'\S', s)
    s = ""
    t = []
    t1 = []
    for i in a:
        if i != ',':
            s += i
        else:
            t.append(s)
            s = ""
    for i in t:
        if len(i) >= n:
            t1.append(i)
    return t1







    return t1

Answer 1 · 2016-06-04T23:18:32Z

June 4, 2016 11:18pm

"dog, cat, baby, balloon, me"

I could describe with regex the string as follows:

there is a word: \w+
there is a comma: ,   
could exist or not a comma: ,?
there is a space:\s
could exist or not a space: \s?

If you look at string you could check that the string is represented by:

there is a word and could exist or not a comma and could exist or not  a space

this in terms of regular expressions is:

'(\w+),?\s?'     two parenthesis means a group what findall
                 is going to return, in this case the word only without comma
                 and space.

that regular expression with findall returns :

['dog', 'cat', 'baby', 'balloon', 'me']

From there you just need to filter with if-else statements to determine
which of them are greater than count and return then in a list

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Francisco Correa

Francisco Correa

Error: "Didn´t get the right output. Output was ['123456', Treehouse', student', 'Kenneth', 'Python']. Length was 6."

1 Answer

Julian Garcia

Julian Garcia