Welcome to the Treehouse Community

The Treehouse Community is a meeting place for developers, designers, and programmers of all backgrounds and skill levels to get support. Collaborate here on code errors or bugs that you need feedback on, or asking for an extra set of eyes on your latest project. Join thousands of Treehouse students and alumni in the community today. (Note: Only Treehouse students can comment or ask questions, but non-students are welcome to browse our conversations.)

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today.

iOS Swift Enums and Structs Structs and their Methods Struct Methods

Posted by Steven Burrows
Steven Burrows
2,607 Points

error in calculation given

I copied and pasted the equation into the screen but I get the following error

swift_lint.swift:12:29: error: 'Double' is not convertible to '()' return (self.amount * (25/100))

But I don't get any errors in xcode

struct.swift 
struct Expense {
    var description: String
    var amount: Double = 0.0

    init (description: String) {
        self.description = description
    }

    func calculateTaxes(percentage: Double){
        return (self.amount * (percentage/100))
    }
    // it should accept only one parameter named 'percentage' of type Double

}
Justin Kendall
Justin Kendall
1,882 Points
Justin Kendall
Justin Kendall
1,882 Points

You need to add a return type of Double. I completely missed it when I just did it. I had to get my brother who does iOS development to look at it to figure out what was wrong with it. It should look like this:

struct Expense {
    var description: String
    var amount: Double = 0.0

    init (description: String) {
        self.description = description
    }

    // add the calculateTaxes method here
    // it should accept only one parameter named 'percentage' of type Double
    func calculateTaxes(percentage: Double) -> Double {
      return (self.amount * (percentage/100))
    }
}