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Python Python Collections (2016, retired 2019) Dictionaries Word Count

error on wordcount.py, not getting the expected output

def word_count(st): list1 = (st.lower()).split(" ") dict1= dict() for word in list1: dict1[word] = (st.lower()).count(word) return (dict1)

wordcount.py
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(st):
    list1 = (st.lower()).split(" ")
    dict1= dict()
    for word in list1:
        dict1[word] = (st.lower()).count(word)
    return(dict1)

2 Answers

Steven Parker
Steven Parker
231,269 Points

I notice that you make a new list variable named "list1", and use it for iteration. But when you update the dictionary "dict1", you count the words in the lowercased string which is likely to generate an inaccurate count.

Also, to split on "all whitespace", leave the argument to "split" empty. Providing a space causes it to split only on individual spaces.

yes , once i corrected both the split function and the count on list instead of string, it worked . Thanks!