Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trial
Rujuta Shinde
1,712 Pointserror on wordcount.py, not getting the expected output
def word_count(st): list1 = (st.lower()).split(" ") dict1= dict() for word in list1: dict1[word] = (st.lower()).count(word) return (dict1)
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(st):
list1 = (st.lower()).split(" ")
dict1= dict()
for word in list1:
dict1[word] = (st.lower()).count(word)
return(dict1)
2 Answers
Steven Parker
229,644 PointsI notice that you make a new list variable named "list1", and use it for iteration. But when you update the dictionary "dict1", you count the words in the lowercased string which is likely to generate an inaccurate count.
Also, to split on "all whitespace", leave the argument to "split" empty. Providing a space causes it to split only on individual spaces.
Rujuta Shinde
1,712 Pointsyes , once i corrected both the split function and the count on list instead of string, it worked . Thanks!