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Python Python Collections (2016, retired 2019) Dictionaries String Formatting with Dictionaries

Posted by Parth Pandya
Parth Pandya
678 Points

Error: string_factory() missing 1 required positional argument: 'template', but works in IDE

Heres my code, I keep getting the error mentioned in the title:

dicts = [ {'name': 'Michelangelo', 'food': 'PIZZA'}, {'name': 'Garfield', 'food': 'lasanga'}, {'name': 'Walter', 'food': 'pancakes'}, {'name': 'Galactus', 'food': 'worlds'} ]

template = "Hi, I'm {name} and I love to eat {food}!"

def string_factory(dicts, template): strings = [] for items in dicts: strings.append(template.format(**items)) return strings

string_factory(dicts, template)

frankgenova
.a{fill-rule:evenodd;}techdegree
frankgenova
Python Web Development Techdegree Student 15,616 Points

Parth Try posting in markdown, the instructions are in the hyperlink below the posting window. It will look like this.

# Heres my code, I keep getting this error message
# Error: string_factory() missing 1 required positional argument: 'template', but works in IDE

dicts = [ {'name': 'Michelangelo', 'food': 'PIZZA'}, 
{'name': 'Garfield', 'food': 'lasanga'}, 
{'name': 'Walter', 'food': 'pancakes'},
 {'name': 'Galactus', 'food': 'worlds'} ]

template = "Hi, I'm {name} and I love to eat {food}!"

def string_factory(dicts, template): 
strings = [] 
for items in dicts: 
strings.append(template.format(**items)) 
return strings

string_factory(dicts, template)
frankgenova
.a{fill-rule:evenodd;}techdegree
frankgenova
Python Web Development Techdegree Student 15,616 Points

template is a global variable established outside of the loop, I don't think you have to pass it to the routine, however I'm not sure that is what the issue is

1 Answer

Steven Parker
Steven Parker
229,786 Points
Steven Parker
Steven Parker
229,786 Points

You should only take one argument.

The instructions say to write a function "that accepts a list of dictionaries as an argument". But your function requires a list of dictionaries and a template. You'll make use of the global template in your function, you won't get one as an argument.

And just define your function. Don't also call it (or define your own list of dicts).