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Ingunn Augdal Fløvig
1,507 PointsError: "Unexpected non-void return value in void function" trying to make a function to return the remainder value
The task is "In this task we're going to write a simple function that takes two numbers and returns the remainder of dividing one number by the other.
Step 1: Declare a function named getRemainder that takes two parameters, aand b, both of type Int, and returns the value, also of type Int, obtained by carrying out the operation a modulo b. In case you've forgotten, the modulo operator is also called the remainder operator.
Step 2: The local names of the parameters are convenient but they make it hard to figure out the meaning of the function when we call it. Add two external names - value, for the first parameter and divisor for the second."
I tried making a constant named remainder and storing a%b in that, and then return that value, but I'm not sure why this doesn't work.
// Enter your code below
func getRemainder(value a: Int, divisor b: Int) {
let remainder: Int = (a % b)
return remainder
}
2 Answers
Rogier Nitschelm
iOS Development Techdegree Student 5,461 PointsWhat the compiler is saying, is that you are returning a value (the remainder), but the function signature does not specify a return value. When you return a value from a function, you will have to write it out. Like so:
func getRemainder(...) -> Int {
...
return someNumber
}
Rogier Nitschelm
iOS Development Techdegree Student 5,461 PointsSwift will only infer the return type when there is no return value. So you could write the absence of a return value in two ways:
func someFuncA() {
...
}
// or
func someFuncB() -> Void {
...
}
Other than that Swift won't infer the return type. I think they choose to be explicit about it.
Ingunn Augdal Fløvig
1,507 PointsIngunn Augdal Fløvig
1,507 PointsThat worked, thanks! Do I always have to specify the type of the return value when creating a function? Can't Swift infer it?