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JavaScript AJAX Basics (retiring) AJAX and APIs Displaying the Photos

Posted by georgeprofenza
georgeprofenza
10,914 Points

Error using a custom function name for the callback

If I use the displayPhoto function as the video suggests I get this error:

Uncaught ReferenceError: jsonFlickrFeed is not definedphotos_public.gne?format=jsoncallback=jQuery111206818820328917354_1429472370664&tags=Dog&format=jso…:1 (anonymous function)

Here's my code so far, with a few tweaks based on the JQuery basics course:

function displayPhoto(data){
  var $photos = $('<ul>');
  $.each(data.items,function(i,photo){
    var $li = $('<li class="grid-25 tabled-grid-50">');
    var $a  = $('<a href="'+photo.link+'" class="image">');
    var $img = $('<img src="'+photo.media.m+'" >');
    $a.append($img);
    $li.append($a);
    $photos.append($li);
  });
  $('#photos').html($photos);
}
$(document).ready(function(){
  $('button').click(
    function(){
      $('button').removeClass("selected");
      $(this).addClass("selected");
      var flickrAPI = "http://api.flickr.com/services/feeds/photos_public.gne?format=jsoncallback=?";
      var animal = $(this).text();
      $.getJSON(flickrAPI,{tags:animal,format:"json"},displayPhoto);
    }
  );
});

If I change displayPhoto to jsonFlickrFeed the code works, but I'm wondering why didn't the displayPhoto function work ?

1 Answer

Marcus Parsons
Marcus Parsons
15,719 Points

Hey George,

What's wrong is that your API url has a "format=" in there that shouldn't be there. Remove the "format=" from your API url so that it reads like so:

http://api.flickr.com/services/feeds/photos_public.gne?jsoncallback=?

georgeprofenza
georgeprofenza
10,914 Points

I see, didn't pay attention to details there. Thank you

Marcus Parsons
Marcus Parsons
15,719 Points

You're welcome! :)