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Java Java Objects (Retired) Meet Objects Privacy and Methods

Stayl T
Stayl T
968 Points
Posted by Stayl T
Stayl T
968 Points

Error using System.out.println!

If I use println instead of printf in this line of code it shows error. Why?

System.out.println("The character's name is %s. ",dispenser.mCharacterName);

4 Answers

jcorum
jcorum
71,830 Points

printf() expects to see one or more format specifiers like %s, and to replace them with variables. println() does not.

So in your code:

System.out.println("The character's name is %s. ",dispenser.mCharacterName);

println() doesn't know what to do with the comma and the variable after the comma.

Stayl T
Stayl T
968 Points
Stayl T
Stayl T
968 Points

Thanks a lot!

Suraj Ahuja
Suraj Ahuja
1,318 Points
Suraj Ahuja
Suraj Ahuja
1,318 Points

try writing System.out.println("The characters name is "+dispenser.mCharacterName); println uses concat to attach values.Hope it helps

Stayl T
Stayl T
968 Points
Stayl T
Stayl T
968 Points

That really works! Thanks!

osman musse
osman musse
100 Points
osman musse
osman musse
100 Points

Println can not use %s because it is a formated string .Print.out.ln can only use normal strings like "osman" Buy Print.out.printf can use formated string like %s so cah

osman musse
osman musse
100 Points
osman musse
osman musse
100 Points

so use print.out.printf instead of print.out.ln