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Java Java Objects (Retired) Harnessing the Power of Objects Handling Exceptions

Error when trying to print the error i caught.

Why does this program fail?

public class Main {
    public static void main(String[] args) {
        GoKart kart = new GoKart("yellow");
        if (kart.isBatteryEmpty()) {
          System.out.println("The battery is empty");
      catch (IllegalArgumentException iae) {
        System.out.println("Error: %s/n.",iae.getMessage());

1 Answer

Very close. You've used println when you really need printf. Since you are using the %s format specifier, you'll need printf. println won't be able to process this kind of formatting.