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Start your free trialDrew Greene
5,086 PointsEven and odd loop
Having trouble with this one. I have tried changing several things and looked through the past questions people have asked but can't figure it out. Any ideas?
import random
def even_odd(num):
# If % 2 is 0, the number is even.
# Since 0 is falsey, we have to invert it with not.
return not num % 2
start = 5
while start > 0:
result = even_odd(random.randint(1, 99))
if result == 0
print("{} is even".format(result))
else:
print("{} is odd".format(result))
start -= 1
1 Answer
Steven Parker
231,269 PointsSince it re-checks task 1 first, it says that if there is a syntax error.
In this case it is because there is no colon at the end of the "if" statement.
Fixing that will pass the challenge, but you might want to know that to test something for "truthy" you only need to name it, so you could just write "while start:
".
This also goes for testing boolean values, so you could write "if result:
".
Drew Greene
5,086 PointsDrew Greene
5,086 PointsAlso, it's telling me that Task 1 is no longer passing