## Welcome to the Treehouse Community

The Treehouse Community is a meeting place for developers, designers, and programmers of all backgrounds and skill levels to get support. Collaborate here on code errors or bugs that you need feedback on, or asking for an extra set of eyes on your latest project. Join thousands of Treehouse students and alumni in the community today. (Note: Only Treehouse students can comment or ask questions, but non-students are welcome to browse our conversations.)

### Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today. PLUS

# even or odd loop

The error message I am getting is "Wrong number of prints". Any idea what he problem could be?

even.py
```import random

start = 5

def even_odd(num):
# If % 2 is 0, the number is even.
# Since 0 is falsey, we have to invert it with not.
return not num % 2

while start == 5:
asd = random.randint(1, 99)
if even_odd(asd):
print("{} is even".format(asd))
else:
print("{} is odd".format(asd))
start -= 1
``` MOD

Hey Dav,

The problem lies with the condition you set for the while loop. You have `while start == 5` which will run the loop only once, as the decrement will make the next iteration equal to 4. Other than that, your code is all correct. The challenge want the loop to run all 5 times, so the condition you need will be `> 0`. This way with each loop the value will decrement by one until the `start` variable is zero.

Below is the corrected code. I hope it'll make sense. :)

```import random

start = 5

def even_odd(num):
# If % 2 is 0, the number is even.
# Since 0 is falsey, we have to invert it with not.
return not num % 2

while start > 0:
asd = random.randint(1, 99)
if even_odd(asd):
print("{} is even".format(asd))
else:
print("{} is odd".format(asd))
start -= 1
```

Keep Coding! 