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Python Python Basics (2015) Letter Game App Even or Odd Loop

Dav Wal
PLUS
Dav Wal
Courses Plus Student 715 Points

even or odd loop

The error message I am getting is "Wrong number of prints". Any idea what he problem could be?

even.py
import random

start = 5

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

while start == 5:
    asd = random.randint(1, 99)
    if even_odd(asd):
        print("{} is even".format(asd))
    else:
        print("{} is odd".format(asd))
    start -= 1

1 Answer

Jason Anders
MOD
Jason Anders
Treehouse Moderator 145,680 Points

Hey Dav,

The problem lies with the condition you set for the while loop. You have while start == 5 which will run the loop only once, as the decrement will make the next iteration equal to 4. Other than that, your code is all correct. :thumbsup:

The challenge want the loop to run all 5 times, so the condition you need will be > 0. This way with each loop the value will decrement by one until the start variable is zero.

Below is the corrected code. I hope it'll make sense. :)

import random

start = 5

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

while start > 0:
    asd = random.randint(1, 99)
    if even_odd(asd):
        print("{} is even".format(asd))
    else:
        print("{} is odd".format(asd))
    start -= 1

Keep Coding! :dizzy:

Dav Wal
Dav Wal
Courses Plus Student 715 Points

Thank you for the clear and speedy answer.

Boonsuen Oh
Boonsuen Oh
18,788 Points

No need to say while start is bigger than 0.