Challenge Task 1 of 1
This one should be short and sweet. Write a function named even_odd that takes a single argument, a number. return True if the number is even, or False if the number is odd. You can use % 2 to find out the remainder when dividing a number by 2. Even numbers won't have a remainder....
PS: i'm a bit sure all that is missing is defining the 'even' or 'odd' numbers; I just can't recollect how to do it and fit into the eve_odd function. See my code below. Thanks
def even_odd(number): if number == even: return True elif number == odd: return False
Josh Keenan17,751 Points
Here's the solution
def even_odd(number): if number % 2 == 0: return True else: return False
get the remainder when divided by two, and if its 0 its even!