Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Python Basics (2015) Letter Game App Even or Odd Loop

Posted by Noel Guerra
Noel Guerra
940 Points

Even_odd : While loop

Alright, last step but it's a big one. Make a while loop that runs until start is falsey. Inside the loop, use random.randint(1, 99) to get a random number between 1 and 99. If that random number is even (use even_odd to find out), print "{} is even", putting the random number in the hole. Otherwise, print "{} is odd", again using the random number. Finally, decrement start by 1. I know it's a lot, but I know you can do it!

not sure what I'm doing wrong here please help

even.py 
import random

start = 5

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2



while start:
    random_num = random.randint(1, 99)
    if even_odd(random_num) == True
        print("{} is even".format(random_num))
    else:
        print("{} is odd".format(random_num))

    start -=1

1 Answer

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

You just have one little typo — your "if" statement is missing the colon at the end. Otherwise, good job! :+1:

Optionally, you can leave off the " == True" part, since anything that returns a boolean (true/false) value can be tested by itself without a comparison.

Noel Guerra
Noel Guerra
940 Points

Thanks ! I can always count on you!