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Python Python Basics (2015) Letter Game App Even or Odd Loop

Gabriel Rosser
Gabriel Rosser
713 Points

even.py "take 1 no longer passing"

Alright, last step but it's a big one. Make a while loop that runs until start is falsey. Inside the loop, use random.randint(1, 99) to get a random number between 1 and 99. If that random number is even (use even_odd to find out), print "{} is even", putting the random number in the hole. Otherwise, print "{} is odd", again using the random number. Finally, decrement start by 1. I know it's a lot, but I know you can do it!

Having trouble figuring out why task 1 isn't passing?

even.py
import random

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2
#Task 3 of 3 
#Alright, last step but it's a big one.
#Make a while loop that runs until start is falsey. start is truthy)
start = 5
while start:
    # Inside the loop, use random.randint(1, 99) to get a
    # random number between 1 and 99. 
    number = random.randit(1, 99)

    #if that random number is even(use even_odd to find out)...
    if even_odd(number):
        # print "{} is even", putting the random number in the hole.
        print("{} is even".format(number))
        # Otherwise,...
    else:
        # print "{} is odd", again using the random number.
        print("{} is odd".format(number))
        # Finally, decrement start by 1.
    start -= 1

1 Answer

Steven Parker
Steven Parker
229,952 Points

You just have a typo.

You wrote randit, but the method name should be randint.

Otherwise, a truly beautiful job! :+1: