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Python Django Basics Model Administration First app view

Utkarsh Gupta
Utkarsh Gupta
546 Points
Posted by Utkarsh Gupta
Utkarsh Gupta
546 Points

Everything is correct. Why it ain't working?

I just can't find out what is wrong with the solution I have written.

articles/views.py 
from django.http import HttpResponse
from .models import Article
# Write your views here

def article_list(requests):
   articles = Article.objects.all()
   count = len(articles)
   return HttpResponse("There are " + count + " articles.")

1 Answer

Jennifer Nordell
seal-mask
STAFF
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Jennifer Nordell
Treehouse Teacher
Jennifer Nordell
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher

Hi there! You're doing very well so far. But count is an integer. And it needs to be a string to be concatenated. So here you have two choices to solve this challenge. You can either convert the value in count to a string and use concatenation, or you can leave it as it is and use interpolation.

Using interpolation:

count = len(articles)
return HttpResponse("There are {count} articles.")

Using concatenation:

count = str(len(articles))
return HttpResponse("There are " + count + " articles.")

Note that I've listed them in order of my personal preference. Hope this helps! :sparkles:

Utkarsh Gupta
Utkarsh Gupta
546 Points
Utkarsh Gupta
Utkarsh Gupta
546 Points

Thanks a lot, Jennifer! :) It worked. But I had read somewhere that we can concatenate strings and int in Python due to polymorphism. Is that a feature of version other than python3 only? Or, Do I need to correct my knowledge?