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JavaScript AJAX Basics (retiring) AJAX and APIs Call the jQuery $.getJSON method

Raeed Sabree
Raeed Sabree
10,664 Points

Everything's in place to send the AJAX request: you've specified the URL, a data object, and a callback function. Use jQ

Everything's in place to send the AJAX request: you've specified the URL, a data object, and a callback function. Use jQuery's $.getJSON() method to make the AJAX call.

what am i doing wrong?

weather.js
$(document).ready(function() {

  var weatherAPI = 'http://api.openweathermap.org/data/2.5/weather';
  var data = {
    q : "Portland,OR",
    units : "metric"
  };
  function showWeather(weatherReport) {
    $('#temperature').text(weatherReport.main.temp);
  }
  $.getJSON(weatherAPI, data,  function )
});
index.html
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>What's the Weather Like?</title>
  <script src="jquery.js"></script>
  <script src="weather.js"></script>
</head>
<body>
  <div id="main">
    <h1>Current temperature: <span id="temperature"></span>&deg;</h1>
  </div>
</body>
</html>

1 Answer

Simon Coates
Simon Coates
28,694 Points

$.getJSON(weatherAPI, data, function ) - function is a keyword, i think. YOu probably want to be passing in a function variable. the following seems to pass test

$(document).ready(function() {

  var weatherAPI = 'http://api.openweathermap.org/data/2.5/weather';
  var data = {
    q : "Portland,OR",
    units : "metric"
  };
  function showWeather(weatherReport) {
    $('#temperature').text(weatherReport.main.temp);
  }
  $.getJSON(weatherAPI, data,  showWeather )
});
Raeed Sabree
Raeed Sabree
10,664 Points

so what do i put for the last thing? i put function and that didnt work then i put function variable and then that didnt work

Simon Coates
Simon Coates
28,694 Points

the code i posted above (you may need to refresh) works.