Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community!
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.Start your free trial
How do you make "except" accept all arguments? The last part it confusing me.
# EXAMPLES # squared(5) would return 25 # squared("2") would return 4 # squared("tim") would return "timtimtim" def squared(num): try: return num ** 2 except: return num * len(num)
Chris FreemanTreehouse Moderator 68,404 Points
The issue isn't that the
except is missing an error type to accept. Using
except without an error type does accept all errors.
The issue is that
squared("2") does raise an error an returns the incorrect result of
"2" (the length times the string) when it should return
You need to attempt converting
num to an int() for the case of a string of numbers within the
Post back if you need more help. Good luck!!!