How do you make "except" accept all arguments? The last part it confusing me.
# EXAMPLES # squared(5) would return 25 # squared("2") would return 4 # squared("tim") would return "timtimtim" def squared(num): try: return num ** 2 except: return num * len(num)
Chris FreemanTreehouse Moderator 56,837 Points
The issue isn't that the
except is missing an error type to accept. Using
except without an error type does accept all errors.
The issue is that
squared("2") does raise an error an returns the incorrect result of
"2" (the length times the string) when it should return
You need to attempt converting
num to an int() for the case of a string of numbers within the
Post back if you need more help. Good luck!!!