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Raghunath Ramaiah
496 Pointsexceptions.py
I coded the script as same as kenneth as below but i get error in workspases. Please help and also getting same error for all the functions which i created
try: count = int(input("please give me a number? ")) except ValueError: print("that is not number!" else: print("Hi " * count)
AND GETTING THE BELOW ERROR
python exceptions.py
File "<stdin>", line 1
python exceptions.py
^
SyntaxError: invalid syntax
3 Answers
behar
10,799 PointsHey Raghunath! Please use the markdown cheat sheet below the "add an answer" area. This shows how to format code which makes it a lot easier to debug.
From what I can see tho you have a couple of errors. One is that you didn't close one of your print statements, and you also are adding an else statement after your exception, which you shouldn't do.
Raghunath Ramaiah
496 PointsPlease see the exceptions.py videos from Kenneth videos with the same code. But for kenneth its running successfully where as i type in the same and try to run i get the error, this is not only for one program it happens to me for simple print function stored in a file and try to run.
Raghunath Ramaiah
496 PointsThank You its working now as i was running from interpreter and i did a exit() and ran the program from console it ran smoothly.