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Start your free trialSohail Mirza
Python Web Development Techdegree Student 5,158 Pointsexplanation of how the code works
I have got this code from a previous student. I am trying to reverse engineer it but finding it difficult. Could someone please break this down for how this works from line 3 downwards
COURSES = {
"Python Basics": {"Python", "functions", "variables",
"booleans", "integers", "floats",
"arrays", "strings", "exceptions",
"conditions", "input", "loops"},
"Java Basics": {"Java", "strings", "variables",
"input", "exceptions", "integers",
"booleans", "loops"},
"PHP Basics": {"PHP", "variables", "conditions",
"integers", "floats", "strings",
"booleans", "HTML"},
"Ruby Basics": {"Ruby", "strings", "floats",
"integers", "conditions",
"functions", "input"}
}
def covers(x):
courses_list = []
for course in COURSES:
if x.intersection(COURSES[course]):
courses_list.append(course)
return courses_list
1 Answer
Steven Parker
231,275 PointsHere's a breakdown:
courses_list = [] # start with an empty list
for course in COURSES: # check each course, one at a time
if x.intersection(COURSES[course]): # if the set (x) has anything in common with the course
courses_list.append(course) # then add the name of the course to the list
return courses_list # finally return the new list
Note that an intersection is only those items both sets have in common. If it is empty, it will be "falsey" to the "if". But if there is at least one thing in it, it will be "truthy".
Does that clear it up?