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Christopher Ponce De Leon
220 PointsExplanation of void
In the video Douglass Turner said that when your function has a return type of void it means that the function would not return anything;
But when he calls the function in main() it returns something?
2 Answers
Seab Jackson
5,692 PointsActually he's right. When the function has a return type of void it doesn't return anything. The function main() though has a return type, and that's why we declare it as: int main(). Main is expecting a return value that is an integer. It turns out that return 0 is reserved for implying that our program was executed successfully, and that no errors occurred in the program. Thus, this return value was for the main function, and not for the scope_it() function.
Vrezh Gulyan
11,161 PointsThe answer to your question is that the function truly returns nothing. That is why its return type is void. The printing happens inside of the void function. When we call it from main , print gets executed inside of scope_it_out and prints to the console.