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iOS Swift 2.0 Functions Function Parameters Function Parameters

External & Local Parameters

Not sure why this isn't working?

Challenge Task 1 of 2

In this task we're going to write a simple function that takes two numbers and returns the remainder of dividing one number by the other.

Step 1: Declare a function named getRemainder that takes two parameters, aand b, both of type Int, and returns the value, also of type Int, obtained by carrying out the operation a modulo b. In case you've forgotten, the modulo operator is also called the remainder operator.

Step 2: The local names of the parameters are convenient but they make it hard to figure out the meaning of the function when we call it. Add two external names - value, for the first parameter and divisor for the second.

/Users/mattconway/Desktop/Screen Shot 2016-01-18 at 3.02.22 PM.png

functions.swift
// Enter your code below
func getRemainder(value a: Int, divisor b: Int) -> Int {
return a % b
}
getRemainder(value: a, divisor: b)
Ashleigh Nombre
Ashleigh Nombre
2,308 Points

The value you need to return is an Integer. You stated in your code that the

value a is of type Int so now you know what your missing.

if you return a % b what is their value

2 Answers

Ok, I see what you mean about the value. I thought if you put a "0" instead of "a" and "b", it can't be any other numbers except 0. However, "0" did not work in the Xcodes playground, but different numbers worked. The zero, instead of the letters, worked in the challenge. Thanks for explaining.

Ashleigh Nombre
Ashleigh Nombre
2,308 Points

Anytime if you have any questions you can reach me on skype @ ashleigh.nombre

I am hearing impaired, so Skype probably wouldn't work for me, unless you know sign language!! :-) Email, text, or the video relay works for me ... Thanks for your offer to help anytime.