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Start your free trialMarion Giraud
7,145 PointsExtra credit (fizz buzz)
That is what I tried to do, hope it will be nice. Thank you, Marion
for (var counter = 100; counter > 0; counter--) {
if (counter %5 == 0 && counter %3 == 0) {
console.log('fizzbuzz');
} else if (counter %5 == 0) {
console.log('buzz');
} else if (counter %3 == 0 ) {
console.log('fizz');
} else {
console.log(counter)
}
}
3 Answers
Erik McClintock
45,783 PointsLooks good, Marion! You can open up the console (in the developer tools of your browser) and paste your code in to see it in action, then you can verify yourself whether or not things are running as you'd expect :)
Keep it up!
Erik
Marion Giraud
7,145 PointsThanks Erik for your help !
Marion
Michael Bianchi
2,488 Points<html> <head> <script> for (var i = 1; i < 101; i++){
if((i % 3 == 0)){
console.log("fizz")}
else if(i % 5 == 0){
console.log("buzz");}
else {
console.log(i);}
}
</script>
</head>
</html>