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JavaScript

Posted by Jeroen Guns
Jeroen Guns
1,206 Points

EXTRA CREDIT fizzbuzz assignment HELP NEEDED (code inside) beginner.

So I have been working on an extra credit assignment for javascript but I can't seem to figure it out.. This is the assignment:

Extra Credit Fizz Buzz

Write a program that loops through the numbers 1 through 100. Each number should be printed to the console, using console.log(). However, if the number is a multiple of 3, don't print the number, instead print the word "fizz". If the number is a multiple of 5, print "buzz" instead of the number. If it is a multiple of 3 and a multiple of 5, print "fizzbuzz" instead of the number.

Hint. Use loops and if/else statments. In javascript the % is the modulo, or remainder operator. a % b evaluates to the remainder of a divided by b. 11 % 3 is equal to 2.

My code so far:

for (var teller=1;teller <101;teller = teller +1){ console.log(teller)

if (teller %3){
} else {
    console.log("fizz");
}

if (teller %5){
    } else {
    console.log("buzz");
}

}

Problems:

1) It doesn't replace the numbers but instead goes like: 1,2,3,fizz, 4, 5, buzz, etc. (It should be 1,2,fizz, 4, buzz, etc.)

2) how do I code multiple if's? (if the number is a multiple of 3 AND 5)

If been trying to crack it for a couple of hours, but can't find it. Any help?

Thanks.

Jeroen

5 Answers

Ben Rubin
Ben Rubin
Courses Plus Student 14,658 Points

I recommend using an if/else block, rather than multiple separate if statements. It makes the code easier to read. Here's the flowchart of what you want to do:

  1. If the number is divisible by 3 and 5, print "fizzbuzz".
  2. Else if the number is divisible by 3, print "fizz".
  3. Else if the number is divisible by 5, print "buzz".
  4. Else print the number.
for (var i  = 1; i <= 100; i++)         // i++ is a shorthand way of writing i = i + 1
{
   // This is how you check multiple conditions in a single if statement.  The && means "and".  You can do an "or" by using ||
   if (i % 3 == 0 && i % 5 == 0)
   {
      console.log("fizzbuzz");
   }
   else if (i % 3 == 0)
   {
      console.log("fizz");
   }
   else if (i % 5 == 0)
   {
       console.log("buzz");
   }
   else
   {
      console.log(i);
   }
}

You could simplify the "divisible by 3 and 5" if statement because if a number is divisible by 3 and by 5, it it also divisible by 15. So you could just check for divisibility by 15 instead of checking 3 and 5. But both ways work.

Another thing; it's better to do if (i % 3 == 0) instead of doing if (i % 3) and putting the log statement in the else block. Both ways will work, but you want to avoid having an if statement with an empty body and only having code in the else block.

Nicholas Chan
Nicholas Chan
1,281 Points

Hi Ben, I am working on this assignment too. I would like to know why is it == 0 (false) instead of 1(true) if were to print the word when it meets the condition?

nhcvwcfhka
nhcvwcfhka
3,902 Points

While Ben has the best answer, I am fairly certain that SEVERAL concepts are missing from the source material that will make this example difficult for some to follow. 1) i++ as ( an incriminator as you showed in your comments) 2) the difference between an assigner =, equals ==, and strictly equals === 3) Logical AND && (as you showed in your comments) 4) else if

//Mine is almost identical to Ben's. I just used strictly equal instead of equals. It's just kinda a habit I got into.

for( var i = 1; i <= 100; i++ ){  // i++ as the shorthand incriminator 
    if( i % 3 === 0 ){
        console.log("Fizz");
    }else if( i % 5 === 0 ){
        console.log("Buzz");
    }else if( i % 3 === 0  && i % 5 === 0 ){   // && is logical AND
        console.log("Fizz Buzz");
    }else{
        console.log( i );
    }
}
Dallin Evans
PLUS
Dallin Evans
Courses Plus Student 193 Points
Dallin Evans
Dallin Evans
Courses Plus Student 193 Points 
if (teller %3){
      console.log("fizz");
      break;
}
if (teller %5){
      console.log("buzz");
      break;
}
 console.log(teller);

Break the current loop if teller is %3 or %5 to stop it from printing both the string and the number.

Jeroen Guns
Jeroen Guns
1,206 Points
Jeroen Guns
Jeroen Guns
1,206 Points

Thanks guys!! much appreciated.

Ben Rubin
PLUS
Ben Rubin
Courses Plus Student 14,658 Points
Ben Rubin
Ben Rubin
Courses Plus Student 14,658 Points

Nicholas - the modulus operator (the % sign) performs a division, but the result is the remainder (instead of the result being the quotient like in regular division). Some examples:

  • 13 % 4 = 1 (13 / 4 = 3 remainder 1)
  • 15 % 3 = 0 (15 / 3 = 5 remainder 0)
  • 27 % 5 = 2 (27 / 5 = 5 remainder 2)
  • 15 % 5 = 0 (15 / 5 = 3 remainder 0)

As you can see, the result of the modulus operator only gives a result of 0 if the first number is evenly divisible by the second number.

The question says you only want to print the words if the number is a multiple of 3 or a multiple of 5. If a number is a multiple of 3, is has to be evenly divisible by 3. If a number is a multiple of 5, it has to be evenly divisible by 5, and so on. The if` statements are not really checking for true or false per se; they're checking to see if the result of the modulus operation is zero or is non-zero.

Nicholas Chan
Nicholas Chan
1,281 Points

Thanks so much for the answer. Now I understand what it means already, it's basically checking whether the calculation returns the wanted result instead of true or false answer. Thanks again.

Thomas Lahoud
Thomas Lahoud
6,092 Points
Thomas Lahoud
Thomas Lahoud
6,092 Points

this is a tough question - there was no where near enough prep for this stuff.