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Java

Posted by eric Crawford
eric Crawford
2,381 Points

Extra Credit question at end of Java Basics, stumped.

Ive read the question where Craig and Ken both answered this but i still can't get Java to run more than one word from my String badWords = "nerd dork jerk";

I would have to type "nerd dork jerk" for it to work, and im trying to get nerd or dork to work by themselves.

Here's my code, i feel stupid!

import java.io.Console;

public class TreeStory {

public static void main(String[] args) {
    Console console = System.console();
    /*  Some terms:
        noun - Person, place or thing
        verb - An action
        adjective - A description used to modify or describe a noun
        Enter your amazing code here!
    */
  //__Name__is a__adjective__ __noun__.  They are always __adverb__ __verb__.
  String ageAsString = console.readLine("How old are you?  ");
  int age = Integer.parseInt(ageAsString);
  if (age < 13) {
    //Insert exit code
    console.printf("Sorry you must be at least 13 to use this program./n");
    System.exit(0);
  }

  String name = console.readLine("Enter a name:  ");
  String noun;

  String badWords = "nerd";

  boolean isInvalidWord;
  do {
    noun = console.readLine("Enter a noun:  ");
    isInvalidWord = noun.contains(badWords); 

    if (isInvalidWord)  {
      console.printf("That language is not allowed.  Try again.  \n\n");
    }
  } while(isInvalidWord);

  String adjective = console.readLine("Enter an adjective:  "); 
  String adverb = console.readLine("Enter an adverb:  ");
  String verb = console.readLine("Enter a verb ending with -ing:  ");

  console.printf("Your TreeStory:\n---------------\n");
  console.printf("%s is a %s %s.  ", name, adjective, noun);
  console.printf("They are always %s %s. \n", adverb, verb);
}

}

Andrew Gay
Andrew Gay
20,893 Points

Um perhaps try badWords.contains(noun)

2 Answers

Andrew Gay
Andrew Gay
20,893 Points

Personally I would do

String badWords = ":butt:dumb:jerk"

String noun = ":" + input;

The input would be whatever they inputed and stored in a variable input. Now if you run

badWords.contains(noun)

It should work id assume..

eric Crawford
eric Crawford
2,381 Points

Thanx Andrew, it worked!

Andrew Gay
Andrew Gay
20,893 Points

No Problem! If you would like I can always look into a more efficient approach/different ways to get similar results

If you need any help with any programing/tech feel free to add me on skype andrew_carson_gay

I am usually quite to respond!

Just please mention you are from Treehouse or I might not respond :P

Though I do apologize for just handing out the answer XD, though I assume you understand what was the problem correct?

Believe It Or Dot
Believe It Or Dot
3,640 Points
Believe It Or Dot
Believe It Or Dot
3,640 Points

Here's my solution:

import java.io.Console;

public class TreeStoryImproved {

    public static void main(String[] args) {
        Console console = System.console();
        String ageAsString = console.readLine("Enter your age:  ");
        int age = Integer.parseInt(ageAsString);
        if (age < 13) {
            console.printf("Sorry. You're underage.\n");
            System.exit(0);
        }
        String name = console.readLine("Enter a name:  ");
        String adjective = console.readLine("Enter an adjective:  ");
        String noun;
        boolean isInvalidWord;
        String areBadWords = "arse ass asshole bastard bitch bloody bollocks cunt damn fuck goddamn                     godsdamn hell holy shit motherfucker shit shitass son of a bitch son of a motherless goat son of a whore jerk dork";
        do {
            noun = console.readLine("Enter a noun:  ");
            isInvalidWord = areBadWords.toLowerCase().contains(noun.toLowerCase());
            if (isInvalidWord) {
                console.printf("That language is not allowed. Try again. \n\n");
            }
        } while(isInvalidWord);
        String adverb = console.readLine("Enter an adverb:  ");
        String verb = console.readLine("Enter a verb:  ");
        console.printf("%s is a %s %s. They are always %s %s", name, adjective, noun, adverb, verb);
        }
}