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JavaScript

Posted by Nelson J
Nelson J
7,411 Points

FEEDBACK on BONUS CHALLENGE.

// 5. BONUS CHALLENGE: Write a while loop that builds a string of random integers
// between 0 and 9. Stop building the string when the number 8 comes up.
// Be sure that 8 does print as the last character. The resulting string 
// will be a random length.

print('5th Loop:');
text = '';
// Write 5th loop here:

i = Math.floor(Math.random() * 10);

while(i <= 9) {
  i++;

  if(i === 8) {
    text += text.concat(i);
    break;
  } else if(i > 8){

    break;
  }

  text += i + ' ';
}

print(text); // Should print something like `4 7 2 9 8 `, or `9 0 8 ` or `8 `.

1 Answer

Steven Parker
Steven Parker
229,732 Points
Steven Parker
Steven Parker
229,732 Points

Good start, and the code runs without errors, but you have a few issues yet:

  • the "print" function is called but not defined here
  • the code picks only one random number instead of a random number for each digit
  • if the random number picked is 8 or 9, no numbers will be shown at all
  • if the random number picked is less than 8, the numbers shown will be in sequence up to 8
  • the sequence up to 7 will be repeated twice
  • the output will never include "0"

I'll bet you can take care of all these in your next revision. Happy coding!

Nelson J
Nelson J
7,411 Points

As always thanks. I was able to fix it:

let text = '';

let i = Math.floor(Math.random() * 10);

do {

i = Math.floor(Math.random() * 10);

text += i + ' ';

} while(i != 8)



console.log(text);
Steven Parker
Steven Parker
229,732 Points
Steven Parker
Steven Parker
229,732 Points

Excellent! Concise and efficient!

Two minor suggestions:

  • declare but don't assign "i" outside of the loop (just "let i;")
  • indent the lines inside the loop body for readability

But really good job! :+1: