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Gata Gbemou
364 Pointsfilter method on century20, keep getting error
const years = [1989, 2015, 2000, 1999, 2013, 1973, 2012]; let century20;
// century20 should be: [1989, 2000, 1999, 1973] // Write your code below const newCentury20 = years.filter(year => year.charAt(0)===2000){ return century20.push('newCentury20'); }
const years = [1989, 2015, 2000, 1999, 2013, 1973, 2012];
let century20;
// century20 should be: [1989, 2000, 1999, 1973]
// Write your code below
const newCentury20 = years.filter(year => year.charAt(0)===2000){
return century20.push('newCentury20');
}
2 Answers
Zaid Khan
12,753 PointsHi Gata Gbemou
We use charAt() to get a specified index in a string. We don't have any string in our array. Also no need to push into a new variable. The challenge asks to store in century20.
So you just have to return to the years that come in the twentieth century. So our condition will return all years less than equal to 2000.
Like this:
century20 = years.filter(year => year <= 2000);
Gata Gbemou
364 Pointsconst years = [1989, 2015, 2000, 1999, 2013, 1973, 2012]; let century20;
// century20 should be: [1989, 2000, 1999, 1973] // Write your code below const newCentury20 = years.filter(year => year.charAt(0)===2000){ return century20.push('newCentury20'); }