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Start your free trialdavid Flores
748 PointsFind Answer
What will be the value of the answer variable after the following code is executed? String answer = “”; int code = 2; if (code == 0) { answer = “Blue”; } else if (code == 1) { answer = “Red”; }
//possible answers a. " " b. "Blue" c. "Red" d. None of The Above
I chose "d" because the code is setting the "int code = 2. From what I understood this line of text is setting the code variable to 2, but according to the lesson I was wrong. Cold some one please explain?
5 Answers
Gunjeet Hattar
14,483 PointsString answer = “”;
int code = 2;
if (code == 0) { answer = “Blue”; }
else if (code == 1) { answer = “Red”; }
- The first line initialises the String variable answer to an empty string.
- Next it initialises the value of code to 2
- Since neither of the conditions match i.e. code is neither equal to 0 or 1 thus, the code in the if statements will never be executed and no answer will not be set to Blue or Red
- So if we print out the value of String it will still remain as empty string i.e. " "
Hope that helps.
Jeremy Stenseth
16,916 Pointsanswer = " "; int code = 2; if code is == to 0 then answer is changed to "blue" but its not so answer is still " ". then it checks if code is == 1 if it is answer is changed to ="Red" but its not so answer is still = " "
david Flores
748 PointsOh ok I think I got it. Since the beginning of the code it sets the int variable to 2 the the only logical answer would be "" because there is no 2 option.
Jeremy Stenseth
16,916 PointsCorrect. Answer is set to " " and answer will always be " " unless a condition is met to change it.
david Flores
748 Pointsthank you everyone for you help
W Joel Baker
1,012 PointsI could use some help. I'm still a little lost with this... what exactly is the int code = 2; doing? Since there is no randomGenerator like in the lesson I'm not clear on what is happening here.