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Paul Otieno
6,035 Pointsfind_words causing problems
My code won't work why?
import re
# EXAMPLE:
# >>> find_words(4, "dog, cat, baby, balloon, me")
# ['baby', 'balloon']
def find_words(count, string):
return re.findall(r'\w*{count}', string)
2 Answers
Idan Melamed
16,285 PointsHi Paul, you are really (really) close!
When you write re.findall(r'\w*{count}', string), it actually tries to check if there is 1 or 0 alphabet characters (that's the \w* part) and if it finds one, it continues to look for '{count}'. Because it doesn't find any word in the list which is made of 0 or 1 characters followed by {count}, it returns an empty list.
Here's my solution:
def find_words(count, string):
return re.findall(r'\w' * count + '+', string)
Multiply '\w' by count, to find words that are equal in length to count, then add a '+' to also find words with more than count letters.
I just thought of another solution:
def find_words(count, my_str):
return re.findall(r'\w{%d,}' % count, my_str)
'\w{num,}' is like saying look for at least num straight \w
Hope this helps, Idan.
Paul Otieno
6,035 PointsThank you Idan