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9,090 Pointsfirst and last 4 function, please help! I'm not sure where my slice when wrong?
Make a new function named first_and_last_4. It'll accept a single iterable but, this time, it'll return the first four and last four items as a single value.
def first_4(arr):
first4 = list(arr[0:4])
return first4
def first_and_last_4(arr):
newArr = arr[:]
first4 = list(newArr[0:4])
last4 = list(arr[-4:])
newestArr = first4.extend(last4)
return newestArr
3 Answers
Fergus Clare
12,120 PointsThere is a somewhat more simple solution I believe:
def first_4(x):
return x[:4]
def first_and_last_4(x):
a = list(first_4(x)) #get a new list returned from your first function
return a.extend(x[-4]) #extend the response from the first function with the negative index list
Daniel Svens
6,043 PointsnewestArr = first4.extend(last4) is the problem it doesnt actually contain the list, it contains none because extending first4 with last4 worked an no problems encountered. extend is a void function and wont return anything.
Change your code to
def first_and_last_4(arr):
#newArr = arr[:]
first4 = list(arr[0:4])
last4 = list(arr[-4:])
first4.extend(last4)
#newestArr = first4.extend(last4)
return first4
Hrithik Sharma
6,090 Pointstry solution
def first_and_last_4(y):
first4 = y[:4]
last4 = y[-4:]
return first4 + last4