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Start your free trialFarid Lavizadeh
12,006 PointsFirst image generated is wrong and is not the same as the first option list.
I noticed after using Promise.all the first image is not of the same breed anymore. I believe the same thing happened in the video. Why isn't the image generated the same as the first value of the list?
3 Answers
Paul Brubaker
14,290 PointsWe can get rid of the generateImage function entirely, as well as the request for the first random image, if we make a small change in the fetchBreedImage function, and call it instead of the (now deleted) generateImage function. Giving the breed variable a default value of 'affenpinscher' ensures that the picture matches right away and gives a good intuitive sense of how the page works to the user. The changes to the fetchBreedImage function might look something like this:
function fetchBreedImage() {
const breed = select.value || 'affenpinscher';
card.innerHTML = '<img><p></p>'
const img = card.querySelector('img');
const p = card.querySelector('p');
fetchData(`https://dog.ceo/api/breed/${breed}/images/random`)
.then(data => {
img.src = data.message;
img.alt = breed;
p.textContent = `Click to view more ${breed}s`;
})
}
And the changes to the initial fetchData call look like this:
fetchData('https://dog.ceo/api/breeds/list/all')
.then( data => generateOptions(data.message))
.then(fetchBreedImage())
Steven Parker
231,184 PointsBefore you select a breed, the code deliberately selects a random image.
Blaize Pennington
13,879 PointsThis bothered me as well. So I just called the fetchBreedImage function after the options were generated.
Danny L.
10,837 PointsHi Blaize, this is bothering me as well. I've tried so many different things and tried calling the fetchBreedImage function just as you said but nothing seems to work. How did you do it?
All I could figure out to get it to work was to hard code it like this:
Promise.all([
fetchData("https://dog.ceo/api/breeds/list/all"),
fetchData("https://dog.ceo/api/breed/affenpinscher/images/random"),
// fetchData("https://dog.ceo/api/breeds/image/random")
])
.then(data => {
console.log(data)
const breedList = data[0].message;
// const randomImage = data[2].message;
generateOptions(breedList);
// generateImage(randomImage);
const firstBreed = select[0].value;
const firstImage = data[1].message;
console.log(firstBreed);
console.log(firstImage);
generateImage(firstImage);
});
Ashley Umetsu
9,565 PointsAshley Umetsu
9,565 PointsWorked great! Thanks!