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JavaScript

Posted by Duke Branding
Duke Branding
3,606 Points

Fizz Buzz!

Just curious, but i wonder if anyone else has used a different method than i did for the Fizz Buzz challenge.

Here's what i did:

for ( i=1; i <= 100; i++ ) { if ( i % 3 === 0 ) { console.log("fizz"); } else if ( i % 5 === 0 ) { console.log("buzz"); } else { console.log(i); } }

6 Answers

Andrew Mosley
Andrew Mosley
12,328 Points

If you're trying for smallest amount of code this works:

for(i=0;i<100;)console.log((++i%3?'':'Fizz')+(i%5?'':'Buzz')||i)

Andrew Mosley
Andrew Mosley
12,328 Points
Andrew Mosley
Andrew Mosley
12,328 Points

You'll notice if you pass your loop into the console that you won't actually see "Fizz Buzz" on multiples of 15. That's because your loop is structured to call "fizz" first and then increment the value of i.

Try something like this: for ( i=1; i <= 100; i++ ) { if (i % 15 === 0) { console.log("Fizz Buzz")} else if ( i % 3 === 0 ) { console.log("fizz"); } else if ( i % 5 === 0 ) { console.log("buzz"); } else { console.log(i); } }

Duke Branding
Duke Branding
3,606 Points
Duke Branding
Duke Branding
3,606 Points

i chose a different way to do the assigment. Thanks for pointing out my oversight!

var i = 1;
var inc = function(){ i++}
do
{
    if ( i % 15 === 0 ) 
    {
        console.log("fizz buzz 15");
        inc();
    }
    else if ( i % 5 === 0 )
    {
        console.log("buzz 5");
        inc();
    }
    else if ( i % 3 === 0 )
    {
        console.log("fizz 3")
        inc();
    }
    else 
    {
        console.log(i);
        inc();
    }

}
while ( i < 101 );
Duke Branding
Duke Branding
3,606 Points
Duke Branding
Duke Branding
3,606 Points

Andrew Mosley , i completely skipped over that part of the assignment! You're right!

James Gill
PLUS
James Gill
Courses Plus Student 34,935 Points
James Gill
James Gill
Courses Plus Student 34,935 Points

A little off-topic, but FizzBuzz is a good, small demo of how elegant Python is compared to JS:

for numbers in range(1,101):
    if numbers % 3 == 0 and numbers % 5 == 0:
        print "FizzBuzz"
    elif numbers % 3 == 0:
        print "Fizz"
    elif numbers % 5 == 0:
        print "Buzz"
    else:
        print numbers
Mike Rolih
Mike Rolih
9,766 Points
Mike Rolih
Mike Rolih
9,766 Points

Wondering why the instructor didn't mention the concept of the "else if ()" subset to the if/else loop? Anyway, here is what I wrote and it worked just fine:

for (var i = 1; i < 100; i++) { if (i % 3 === 0 && i % 5 ===0) { console.log("fizzbuzz"); } else if (i % 3 ===0) { console.log("fizz"); } else if (i % 5 === 0) { console.log("buzz"); } else { console.log(i); } }