Fizz buzz challenge

Can't figure it out either. Just skip it for now because it's extra credit.

Hello Tunde,

You currently have (re-formatted for easier reading), which does print the numbers 100 to 1 correctly:

for (var number = 100; number; number = number - 1)
{ 
    console.log(number);
}

What you need to add is a set of if, else conditional statements in the loop to change what you write to the console with console.log. I will give you an example to help illustrate it. In my example I want to count down from 10 to 1 and if it is a multiple of 2 then instead write your name, Tunde:

for (var number = 10; number; number = number - 1)
{ 
    if(number % 2 == 0) {
        console.log("Tunde");
    } else {
        console.log(number);
    }
}

I have created a fiddle so that you can view this code running . I hope this helps clarify how to create the solution, if you have any more questions let me know. Good luck!

Tunde Adegoroye -

My suggestion is to come back to the FizzBuzz exercise after you've completed JavaScript Foundations and have some more experience programming.

LOL ... looks like I too will need to come back to this. I'm brand new to coding. Well, funny thing, I can read most programming and understand what is going on, but never learned the basics of syntax and such to be able to write it.

My code results so far ...

for (var counter = 1; counter < 101; counter = counter +1) {

if (counter%3 == 0) {
    console.log("fizz");
} else(counter)

}

This only prints out 33 fizz and no numbers ... looks like I may be close, but I will come back.

Here is what I used and it worked.

code redacted

So this might be old news but it's something that wasn't covered in the videos: the use of if/else if/else statements.

For example:

if("condition one"){
    console.log("condition one was met");
} else if("condition two"){
    console.log("condition two was met");
} else {
  console.log("remaining content will be output here");
}

Hope this helps without giving away too much.

Hey everyone,

So I've almost got this down. I've got numbers divisible by 3 changing to "Fizz" and numbers visible by 5 changing to "Buzz", but I'm struggling with the last part where you need to change any number divisible by both 3 AND 5 to "Fizzbuzz". It's probably a little farther ahead, but is this where we're supposed to be utilizing either the || or the && operators in the Else If statement?

I had something along the lines of:

else if (Condition 1 || Condition 2) {
console.log("FizzBuzz")
}

Any and all help is appreciated! Used Condition 1 and two because I didn't want to give anything away. (First time forum poster too so my apologies if we're not supposed to post more questions in the Answer sections).

Thanks for the tips guys!

I realise that I cannot add the solution in here, but I will say that these things really helped:

To pass two conditionals (if divisible by 3 and 5) use the && operator.

Another tip, instead of outputting fizz / buzz / fizzbuzz, I outputted the counter's value followed by " is divisible by 3" etc to debug the code as I was writing, enabling me to understand the output better.

I also started with an if statement, then a series of else if statements, followed by an else for all other results that didn't match the above criteria.

Can anyone chime in on how to avoid 'ordering' if, else if and else statements to get the same result, thus allowing flexibility for more complex declarations?

Jamie - Thanks for your looping best practice tip! It was very helpful and I'm sure I'll use it as I continue to take more courses.