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Start your free trialTahani Al-Shumrani
iOS Development Techdegree Student 2,022 PointsFizzBuzz
i tried every thing to solve this challenge but i coud not i don't know way
for n in 1...100 {
if (n % 3 == 0 ) && (n % 5 == 0) {
print ("FizzBuzz")
} else if (n % 3 == 0 ) {
print ("Fizz")
} else if (n % 5 == 0) {
print ("Buzz")
} else {
print( n )
}
}
1 Answer
Jason Anders
Treehouse Moderator 145,860 PointsHey there,
While your code is correct in syntax, it is not following the very specific instructions the challenge asks for:
Step #2 "... You also don't need to define n. It is defined in the function provided ... The challenge also does not need you to loop over a range of values (using for or while). I'll take care of that." -- you created a loop, so that needs to be removed.
Step #3 "Change all your print statements to return statements. For example: print("FizzBuzz") becomes return "FizzBuzz". -- you still have "print", so those need to be changed.
"Note: Do not worry about the default case" -- you have an "else" statement, so that will also need to be deleted.
Overall, just refactor your code to match exactly what the challenge needs to verify the answer and you're good to go.
Keep Coding!