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iOS Swift Collections and Control Flow Control Flow With Conditional Statements FizzBuzz Challenge

Posted by Zhenia Ps
.a{fill-rule:evenodd;}techdegree
Zhenia Ps
iOS Development Techdegree Student 407 Points

FizzBuzz

Hey guys. Not sure why it is not working here with func. I have tested my code in Playground and it was compiled just fine.

Any help is much appreciated.

fizzBuzz.swift 
func fizzBuzz(n: Int) -> String {
  // Enter your code between the two comment markers
for n in 1...100 {
    if n % 3 == 0 && n % 5 == 0 {
        print("FizzBuzz")
    } else if n % 5 == 0 {
        print("Buzz")
    } else if n % 3 == 0 {
        print("Fizz")
  }
}
  // End code
  return "\(n)"
}
Zhenia Ps
.a{fill-rule:evenodd;}techdegree
Zhenia Ps
iOS Development Techdegree Student 407 Points

Wohoo ;) it worked, thanks a bunch. So return is a kind of a command. I thought that print command will return something.. lol ;)

Thanks again

Alexander Davison
Alexander Davison
65,469 Points

The print function just prints some value onto the screen and the return keyword is used for returning values.

Even built-in functions like print actually have a return value. The print function simply returns nil (basically a Swift way of saying "nothing").

Meanwhile, it would be nice to click the Best Answer button located under an answer that has helped you. If you mark a answer as a Best Answer, the user who made the post gets a bonus +12 forum points for that topic. It also helps with the community answer filtering I think :smile:

Thank you for understanding. ~Alex

1 Answer

Alexander Davison
Alexander Davison
65,469 Points

The challenge told you to remove the for loop but keep it's contents.

Also, you should return the FizzBuzz, Fizz and Buzz messages, not print them. :)

I hope this helps.

If you continue to fail, please respond.

~Alex

EDITED

Zhenia Ps
.a{fill-rule:evenodd;}techdegree
Zhenia Ps
iOS Development Techdegree Student 407 Points

Thanks Alex. It's my inattentiveness ;) I have removed for loop, here is the code:

if n % 3 == 0 && n % 5 == 0 {
    print("FizzBuzz")
} else if n % 5 == 0 {
    print("Buzz")
} else if n % 3 == 0 {
    print("Fizz")

}

However I still receive the following error, not sure why it does not like Fizz ;))

Bummer! Double check your logic for Fizz values and make sure you're returning the correct string!

Alexander Davison
Alexander Davison
65,469 Points

Updated my post :)

Check my post again. I also noticed something else that is causing another problem.