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Gibson Smiley
1,923 PointsFizzBuzz
I'm told that my "Buzz" isn't working, though it's the same as both "FizzBuzz" and "Fizz".
func fizzBuzz(n: Int) -> String {
// Enter your code between the two comment markers
for n in 1...100 {
if (n % 3 == 0) && (n % 5 == 0) {
return("FizzBuzz")
} else if (n % 3 == 0) {
return("Fizz")
} else if (n % 5 == 0) {
return("Buzz")
}
}
// End code
return "\(n)"
}
Diego Aguirre
13,211 PointsHi Smiley, like you said your code is absolutely spot on when it comes to writing it in Xcode itself. That being said when it comes to the challenge the instructor is asking you to enter the code in a specific manner as well as committing certain lines.
Pay attention to this direction located on the last line of the challenge: "The challenge also does not need you to loop over a range of values (using for or while). I'll take care of that."
Once you solve that your code will work. Hope that helps.
1 Answer
Pavel Fomchenkov
20,897 PointsHello, Gibson. The instructor says that you do not need the loop inside your function, because his program loops your function outside of the exercise scope. So just get rid of the for-looping lines of your code. Also you do not need the parentheses in the return statement.
Gibson Smiley
1,923 PointsGibson Smiley
1,923 PointsPutting this code in Xcode gives exactly what I need, of course changing "return" to "print" and adding a final "else { print(n)}"