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![Juan Jimenez](https://secure.gravatar.com/avatar/47edeff0cae188a0544c355468f8ad39?s=96&d=https%3A%2F%2Fecs-static.teamtreehouse.com%2Fassets%2Fcontent%2Fdefault_avatar-445fbbabfc8dc9188fb5967fe43322ee0c3e0dd1e10f378bf8343784af5a13eb.webp&r=pg)
Juan Jimenez
4,389 PointsFizzBuzz
It took me an hour to solve FizzBuzz but it checked out. My code was as follows
for _ in 0...n {
if n % 3 == 0 && n % 5 != 0 {return("Fizz")}
else if n % 5 == 0 && n % 3 != 0 {return("Buzz")}
else if n % 3 == 0 && n % 5 == 0 {return("FizzBuzz")}
}
It worked, but I was just curious if there is anything in here that should be improved.
func fizzBuzz(n: Int) -> String {
// Enter your code between the two comment markers
// End code
return "\(n)"
}
1 Answer
![Kevin Tanner](https://uploads.teamtreehouse.com/production/profile-photos/428082/micro_DSC_0140.jpg)
Kevin Tanner
3,385 PointsIf you changed the order of your if statement so you calculate for if it is divisible by 3 and 5 first then you don’t need to have checks for if it is not divisible by 3 or 5.