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Jonathan Lee
1,565 PointsFizzBuzz
Not sure why this case failed to compile. Seemed fine in the playground page.
func fizzBuzz(n: Int) -> String {
// Enter your code between the two comment markers
let n: Int = 15
for n in 1...100 {
if (n%3 == 0) {
return("Fizz")
} else if (n%5 == 0){
return("Buzz")
} else if (n%3 == 0) && (n%5 == 0){
return("FizzBuzz")
} else {
return(n)
}
}
// End code
return "\(n)"
}
5 Answers
Digvijay Jaiswal
5,565 PointsTry the code below. The reason your code is not working is simple, For example if you type 15 you should be getting FizzBuzz but you won't because your first expression also satisfies that 15 % 3 == 0 and jumps out of the loop. I hope it makes sense.
for n in 1...100 {
if (n%3 == 0) && (n%5 == 0)
{ return("FizzBuzz")
} else if (n%5 == 0){
return("Buzz")
} else if (n%3 == 0){
return("Fizz")
} else {
return(n)
Jonathan Lee
1,565 PointsThank You, I had just realized this before your answer, but wasn't sure how to fix it. Before I watch the video that answers the challenge, do you know if the same result can be given using switch and/ or while loops instead of if, else if loops?
Digvijay Jaiswal
5,565 PointsI am not sure about while since this is not a while kinda case, but yes we can totally achieve this by switch.
Jonathan Lee
1,565 PointsI attempted it in a playground page, but am having trouble with Bool not matching type Int.
var n: Int = 0
for n in 1...100 { switch n { case (n%3 == 0): print("Fizz") case (n%5 == 0): print("Buzz") case (n%3 == 0) && (n%5 == 0): print("FizzBuzz") default: print(n) } }
Digvijay Jaiswal
5,565 PointsTry to replace the last case with the first.