Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trial
Ahmed Seddek
iOS Development Techdegree Student 6,448 PointsFizzBuzz
what is the problem in this code it is like the solution in next video and editor said double check logic for fizz values and returning correct string
func fizzBuzz(n: Int) -> String {
// Enter your code between the two comment markers
for n in 1...100
{
if( n % 5 == 0 ) && ( n % 3 == 0 )
{
return "FizzBuzz"
}
else if( n % 5 == 0 )
{
return "Fizz"
}
else if( n % 3 == 0 )
{
return "Buzz"
}
}
// End code
return "\(n)"
}
1 Answer
Jennifer Nordell
Treehouse TeacherHi there! You're doing well, but you missed part of the instructions:
The challenge also does not need you to loop over a range of values (using for or while). I'll take care of that.
So you need to begin by removing your loop. But that still won't entirely fix it. You've gotten "Fizz" and "Buzz" backwards. "Buzz" should be returned when it's evenly divisible by 5 and "Fizz" should be returned when it's evenly divisible by 3.
Give it another shot with these hints in mind!
Ahmed Seddek
iOS Development Techdegree Student 6,448 PointsAhmed Seddek
iOS Development Techdegree Student 6,448 Pointsfirst , thanks for fast replying . second , it is finally worked and I did this change before but I don't know what happen with this editor .