Fizzbuzz challenge

Question

I am currently stuck on the Fizz Buzz challenge, when i go to run the script i get an unexpected token error.  I have a feeling that the issue is in my formatting and i am on the right track for how to actually structure out the code.  I am not looking for an answer just to be pointed in the right direction.
for (var counter =1; counter < 101; counter=counter+1) {
    console.log(counter)
    if (counter%3==0 && counter%5==0) {
        console.log("fizzbuzz");
        }
    else (counter%3==0) {
        console.log("fizz");
        }
    else(counter%5==0){
        console.log("buzz");
        }
    else {
        console.log(counter);
}

Cassio Victor Cadore · Accepted Answer

Yes Andrew, there is a semicolon missing in the first   console.log(counter).
Did you forget it, or just don't think it should be there?
Here you have some info about semicolons and Javascript:
http://www.codecademy.com/blog/78-your-guide-to-semicolons-in-javascript

Andrew Hunt · Answer

Added closing curly brace to the end of else statement, pretty sure i need two there, one to close the else statement and one to close the for loop.  still getting the same error though,  I am not sure i understand the proper placement of semi-colins here.
for (var counter =1; counter < 101; counter=counter+1) {
    console.log(counter)
        if (counter%3==0 && counter%5==0) {
            console.log("fizzbuzz");
            }
        else if(counter%3==0) {
            console.log("fizz");
            }
        else if(counter%5==0){
            console.log("buzz");
            }
        else {
            console.log(counter);}
    }

Cassio Victor Cadore · Answer

Are you sure that you are closing all loops? For, if, else...

Andrew Hunt · Answer

alright, i changed my else statements to else if.  Now i think i am down to some misplaced semi colons or brackets, the new error i get when running the script is unexpected end of input
for (var counter =1; counter < 101; counter=counter+1) {
    console.log(counter)
    if (counter%3==0 && counter%5==0) {
        console.log("fizzbuzz")
        }
    else if(counter%3==0) {
        console.log("fizz")
        }
    else if(counter%5==0){
        console.log("buzz")
        }
    else {
        console.log(counter)
}

David Curtis · Answer

check your usage of if and else

Cassio Victor Cadore · Answer

Hey Andrew!
I'll try to help you wiyhout giving you the answer...
Check how the if...else statement is used!
And if all closures {} are correct!

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Andrew Hunt

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Fizzbuzz challenge

6 Answers

Cassio Victor Cadore

Cassio Victor Cadore

Andrew Hunt

Andrew Hunt

Cassio Victor Cadore

Cassio Victor Cadore

David Curtis

David Curtis

Andrew Hunt

Andrew Hunt

Cassio Victor Cadore

Cassio Victor Cadore

Andrew Hunt

Andrew Hunt