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iOS

Posted by Addison Francisco
Addison Francisco
9,561 Points

FizzBuzz challenge solution

Here is my solution to the FizzBuzz challenge. I decided not to go with the if/else solution and instead try it out with a switch statement. I'm aware it's probably not the best implementation, so I'm interested in any feedback.

func fizzBuzz(n: Int) -> String {

    switch n {
    case n where n % 3 == 0 && n % 5 == 0:
        return "FizzBuzz"
    case n where n % 3 == 0:
        return "Fizz"
    case n where n % 5 == 0:
        return "Buzz"
    default:
        break
    }
    return "\(n)"
}

for n in 1...100 {
    fizzBuzz(n)
}

2 Answers

jcorum
jcorum
71,830 Points
jcorum
jcorum
71,830 Points

Congrats! Looks very nice. It highlights some of the pattern matching and the use of the break keyword, things the video doesn't touch on.

AR Ehsan
AR Ehsan
7,912 Points
AR Ehsan
AR Ehsan
7,912 Points

Great job :)