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Start your free trialAlex Whitlock
iOS Development Techdegree Student 497 PointsFizzBuzz code working perfectly in xCode, won't compile in treehouse.
I've got what seems to be a valid solution to the FizzBuzz problem,, substituting Fizz for every multiple of 3, Buzz for every multiple of 5, and 15 for every multiple of both. It works great in xCode, but when I try to put it into xCode and run it between the lines of code written in , I get a compiler error. Any idea why that might be?
func fizzBuzz(n: Int) -> String {
//Start code here
for i in 1...100 {
if ((n % 3 == 0) && (n % 5 == 0)){
return "FizzBuzz"
} else if (n % 3 == 0) {
return "Fizz"
} else if (n % 5 == 0) {
return "Buzz"
} else {
return (n)
}
}
//end code
return "\(n)"
}
2 Answers
hum4n01d
25,493 PointsYou need to return a string. Try converting the int to a string like this:
Try this:
func fizzBuzz(n: Int) -> String {
//Start code here
for i in 1...100 {
if ((n % 3 == 0) && (n % 5 == 0)){
return "FizzBuzz"
} else if (n % 3 == 0) {
return "Fizz"
} else if (n % 5 == 0) {
return "Buzz"
} else {
return String(n)
}
}
//end code
return "\(n)"
}
Mackenzy Douyon
iOS Development Techdegree Student 2,913 Points//Your code looks great, except the those lines I commented. //copy and paste to compile func fizzBuzz(n: Int) -> String { //Start code here //for i in 1...100 { if ((n % 3 == 0) && (n % 5 == 0)){ return "FizzBuzz" } else if (n % 3 == 0) { return "Fizz" } else if (n % 5 == 0) { return "Buzz" } else { //return (n) //} //} //end code return "(n)" //add one closing bracket }}
fizzBuzz(n: 15)
Alex Whitlock
iOS Development Techdegree Student 497 PointsAlex Whitlock
iOS Development Techdegree Student 497 PointsThat did the trick, thanks!