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iOS Swift 2.0 Collections and Control Flow Control Flow With Conditional Statements FizzBuzz

Von Chucwuemeca
Von Chucwuemeca
4,746 Points

FizzBuzz Compiler is not working?

Here is my code, and I'm quite sure its right. I've seen from other samples that the 'FizzBuzz' statement is first. However if that is the case, I don't know why that is the case.

func fizzBuzz(n: Int) -> String { // Enter your code between the two comment markers if n % 3 == 0 { return "Fizz" } else if n % 5 == 0 { return "Buzz" } else if (n % 3 == 0) && (n % 5 == 0) { return "FizzBuzz" }

// End code return "(n)" }

fizzBuzz.swift
func fizzBuzz(n: Int) -> String {
  // Enter your code between the two comment markers
  if n % 3 == 0 {
        return "Fizz"
    } else if n % 5 == 0 {
        return "Buzz"
    } else if (n % 3 == 0) && (n % 5 == 0) {
        return "FizzBuzz"
    }

  // End code
  return "\(n)"
}

2 Answers

Kourosh Raeen
Kourosh Raeen
23,733 Points

If n is 15 then all three conditions will be true and since you check divisibility by 3 first the function returns "Fizz" instead of "FizzBuzz", so that is why you need to first check to see if the number is divisible by both 3 and 5.

Von Chucwuemeca
Von Chucwuemeca
4,746 Points

Could this be done with a switch statement?