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Start your free trialVon Chucwuemeca
4,746 PointsFizzBuzz Compiler is not working?
Here is my code, and I'm quite sure its right. I've seen from other samples that the 'FizzBuzz' statement is first. However if that is the case, I don't know why that is the case.
func fizzBuzz(n: Int) -> String { // Enter your code between the two comment markers if n % 3 == 0 { return "Fizz" } else if n % 5 == 0 { return "Buzz" } else if (n % 3 == 0) && (n % 5 == 0) { return "FizzBuzz" }
// End code return "(n)" }
func fizzBuzz(n: Int) -> String {
// Enter your code between the two comment markers
if n % 3 == 0 {
return "Fizz"
} else if n % 5 == 0 {
return "Buzz"
} else if (n % 3 == 0) && (n % 5 == 0) {
return "FizzBuzz"
}
// End code
return "\(n)"
}
2 Answers
Kourosh Raeen
23,733 PointsIf n
is 15 then all three conditions will be true and since you check divisibility by 3 first the function returns "Fizz" instead of "FizzBuzz", so that is why you need to first check to see if the number is divisible by both 3 and 5.
Von Chucwuemeca
4,746 PointsThanks
Kourosh Raeen
23,733 PointsYou're welcome!
Von Chucwuemeca
4,746 PointsVon Chucwuemeca
4,746 PointsCould this be done with a switch statement?