fizzbuzz extra credit

Why is this extra credit question presented before the instructor has covered the code necessary to complete it? Or am I missing something?

Thank you, thank, thank you!! That was so simple, wish the instructor had mentioned 'else if' in the video.

Another way to write out the code for the same effect would be wrapping an if/else statement inside another if statement. Here is my code:

for (var n=1; n<=100; n++) {

    if (n%5 === 0){     
        if (n%3 ===0) {
            console.log("fizzbuzz");
        }
        else {
            console.log("buzz");
        }
    }

    else if (n%3 === 0){
        console.log("fizz");
        }

    else {
        console.log(n);
        }

}   

Here is mine using WHILE loop:

var number = 100;

while (number) {
    if (number % 15 == 0) {
        console.log("fizzbuzz");
    } else if (number % 3 == 0) {
        console.log("fizz");
    } else if (number % 5 == 0) {
        console.log("buzz");
    } else {
        console.log(number);
    }   

    number = number - 1;
}

Thank you so much for taking the time to explain all this. I really appreciate it. Regarding the order of the numbers 3 and 5 that occurred when I was changing the order to see if it would make any difference. I forgot to change it back before I copy and pasted it into to my message. I did correct the order before I received Keven's response so I was able to run my code successfully; although as someone else later pointed out I forgot change fizz and buzz to correspond with the correct number. Have a great day!

Just adding my version of FizzBuzz into the conversation :)

for (var i = 1; i <= 100; i++) {
  if (i%3 === 0 && i%5 === 0) {
    console.log("FizzBuzz");
  } else if (i%3 === 0) {
    console.log("Fizz");
  } else if (i%5 === 0) {
    console.log("Buzz");
  } else {    
  console.log(i);
  }
}

Couple of things I've used that I found outside of "class":

1. i++ is shorthand for i = i + 1
2. && is the logical operand, AND. Both expressions need to evaluate as true for the condition to be true.

Sorry, playing around and came up with an alternative version which consists of solely if statements (no if else statements):

for (var number = 1; number <= 100; number++) {

  var output = "";

  if (number%3 === 0) {
    output = output + "Fizz";
  }

  if (number%5 === 0) {
    output = output + "Buzz";
  }

  if (!output) {
    output = number;
  }

  console.log(output);

}

This version starts with an empty string (output) then uses concatenation to add "Fizz" or "Buzz" to the string. It doesn't need another if statement to check for "FizzBuzz"... that case has already been covered.

Finally, if the output string is still empty (i.e. it's a falsy), the current number is assigned to output.

for (var count= 100; count> 0; count--) { if (count% 15 == 0) { console.log("fizzbuzz"); }

else if (count% 5 == 0) {
    console.log("buzz");
}

else if (count% 3 == 0) {
    console.log("fizz");
}

else {
    console.log(count);
}

}

for (var number = 100; number > 0; number--) {
    if (number % 15 == 0) {
        console.log("fizzbuzz");
    }

    else if (number % 5 == 0) {
        console.log("buzz");
    }

    else if (number % 3 == 0) {
        console.log("fizz");
    }

    else {
        console.log(number);
    }
}

Had to fix up Kevin's code. This should work properly. When your loop finds a number divisible by 15. As soon as it hits the first 'if' block, and the condition is true, your console will print out "fizzbuzz" and it will break out of the 'if else/if ' block all together and continue with the loop. It will ignore everything subsequent of the 'if else/if' block as it should.

If the first condition is false, it checks the next condition which is if the number is divisible by '5', if that is true it will break out of the 'if' block and log "fizz" out to the console... this goes for all cases of an "if, else/if" statement.

If you had a made a conditional check of '3' before you made a conditional check of '5', when the condition of '3' is true, it will print "buzz" and break out of the if else/if block and it will never check that last condition of '5'.

Order of execution is crucial as this is a procedural programming paradigm.