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iOS Swift Basics (retired) Control Flow Exercise: FizzBuzz Generator

Alan Grey
Alan Grey
1,856 Points
Posted by Alan Grey
Alan Grey
1,856 Points

FizzBuzz generator: my answer differs from Amit's, but is it a correct answer?

My code differs from Amit's, is it still correct? The main difference is that mine requires a user input, and then returns FizzBuzz/Fizz/Buzz:

var input = 330

var dividedByThree = (input % 3) var dividedByFive = (input % 5)

if dividedByFive == 0 && dividedByThree == 0 { println ("FizzBuzz!") } else if dividedByFive == 0 { println ("Buzz") } else if dividedByThree == 0 { println ("Fizz") } else { println ("(input)") }

Thanks in advance for any replies!

3 Answers

Sean Lee
Sean Lee
5,196 Points
Sean Lee
Sean Lee
5,196 Points

mine was very different as well. I used an index, array and while loop:

var index = 0
let numbers = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 30, 60, 300]

while index < numbers.count {
    if numbers[index]%3==0 && numbers[index]%5==0 
         println("FizzBuzz")
    }
    else if numbers[index]%3==0 {
        println("Fizz")
   }
    else if numbers[index]%5==0 {
        println("Buzz")
    }
    else {
        println(numbers[index])
    }
    index++
}
Felix Salazar
Felix Salazar
3,879 Points
Felix Salazar
Felix Salazar
3,879 Points

Yes, it should work; only detail: the var declarations should be in separated lines. Have you tested it in your playground?

var input = 330

var dividedByThree = (input % 3)
var dividedByFive = (input % 5)

if dividedByFive == 0 && dividedByThree == 0 { 
println ("FizzBuzz!") } 
else if dividedByFive == 0 { 
println ("Buzz") } 
else if dividedByThree == 0 {
 println ("Fizz") } 
else { println ("(input)") }
Frances Angulo
Frances Angulo
5,311 Points
Frances Angulo
Frances Angulo
5,311 Points

I did this without defining the dividends - I realize that I didn't use switch statement, so the else may be unnecessary? 

var number = 25

if number % 3 == 0 && number % 5 == 0 {
    println("fizzbuzz")
} else if number % 5 == 0 {
    println("buzz")
} else if number % 3 == 0 {
    println("fizz")
}
else {
    println("else")
}