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Start your free trialNils Garland
18,416 PointsFizzBuzz Problems :P
So I can't find the problem, does anybody see it? Thanks a lot :D
func fizzBuzz(n: Int) -> String {
// Enter your code between the two comment markers
for n in 1...100 {
if(n % 3 == 0) && (n % 5 == 0) {
return "FizzBuzz"
} else if(n % 3 == 0) {
return "Fizz"
} else if(n % 5 == 0) {
return "Buzz"
} else {
return "\(n)"
}
}
return "\(n)"
}
2 Answers
Jennifer Nordell
Treehouse TeacherHi again! If you're referring to this challenge, then I'd point out that you missed a note in the instructions.
The challenge also does not need you to loop over a range of values (using for or while). I'll take care of that.
If I copy/paste your code into the challenge and then remove the surrounding for loop (including the closed curly brace for that loop), it passes! Your logic is spot on. Hope this helps!
Leandro Pezรกn
Courses Plus Student 2,049 PointsThere's no need for a double return (see the two last ones). Since this is the default case, it should go inside the else curly braces. The code should look something like this:
func fizzBuzz(n: Int) -> String {
if (n % 3 == 0) && (n % 5 == 0) {
return "FizzBuzz"
} else if (n % 3 == 0) {
return "Fizz"
} else if (n % 5 == 0) {
return "Buzz"
} else {
return "\(n)"
}
}
Nils Garland
18,416 PointsThank you for answering :D
Nils Garland
18,416 PointsNils Garland
18,416 PointsThanks again :D