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iOS

FizzBuzz Problems :P

So I can't find the problem, does anybody see it? Thanks a lot :D

func fizzBuzz(n: Int) -> String {
    // Enter your code between the two comment markers
    for n in 1...100 {
        if(n % 3 == 0) && (n % 5 == 0) {
            return "FizzBuzz"
        } else if(n % 3 == 0) {
            return "Fizz"
        } else if(n % 5 == 0) {
            return "Buzz"
        } else {
            return "\(n)"
        }
    }
    return "\(n)"
}

2 Answers

Jennifer Nordell
seal-mask
STAFF
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher

Hi again! If you're referring to this challenge, then I'd point out that you missed a note in the instructions.

The challenge also does not need you to loop over a range of values (using for or while). I'll take care of that.

If I copy/paste your code into the challenge and then remove the surrounding for loop (including the closed curly brace for that loop), it passes! Your logic is spot on. Hope this helps! :sparkles:

Thanks again :D

There's no need for a double return (see the two last ones). Since this is the default case, it should go inside the else curly braces. The code should look something like this:

func fizzBuzz(n: Int) -> String {
    if (n % 3 == 0) && (n % 5 == 0) {
        return "FizzBuzz"
    } else if (n % 3 == 0) {
        return "Fizz"
    } else if (n % 5 == 0) {
         return "Buzz"
    } else {
        return "\(n)"
    }
}

Thank you for answering :D