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Python Python Basics (2015) Shopping List App Break

Henry Moreno
Henry Moreno
1,086 Points
Posted by Henry Moreno
Henry Moreno
1,086 Points

FOR LO0OP

I have added this code and still no work

def loopy(items): shopping_list = [] shopping_list.append(items) for items in shopping_list: print(items)

loopy("apples")
breaks.py 
   def loopy(items):
    shopping_list = [] 
    shopping_list.append(items)
          for items in shopping_list: 
             print(items)

    loopy("apples")

3 Answers

Blaine McCarthy
Blaine McCarthy
17,030 Points
Blaine McCarthy
Blaine McCarthy
17,030 Points

Hello Henry! I had trouble with these, too. You had "for items" when it should be "item". When you type "for item in items", you're telling the program, literally:"For everything individual item in our list, items - I want you to print that individual item.

We .append() to lists when we want to add a new item to them - you can take that out for this challenge

def loopy(items):
    for item in items:
        print(item)
Ted Dunn
Ted Dunn
43,783 Points
Ted Dunn
Ted Dunn
43,783 Points

The challenge is actually separate from what was taking place in the video. Therefore, you do not need to include anything about a shopping list in your code. Your code should only address the functionality specified explicitly in the code challenge.

Thus, for the first part of the challenge you need to create a for loop which prints each "thing" passed into the function via the items parameter.

def loopy(items):
    for item in items:
        print(item)

The second part of the challenge, asks that you break out of the loop if the current item is a string with a value of 'STOP'.

def loopy(items):
    for item in items:
        if item == "STOP":
            break
        print(item)
Henry Moreno
Henry Moreno
1,086 Points
Henry Moreno
Henry Moreno
1,086 Points

Ted: Thanks that was a big help ..Happy Holidays