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Start your free trialTony Brackins
28,766 Pointsformat() argument after ** must be a mapping, not list
Create a function named string_factory that accepts a list of dictionaries and a string. Return a new list build by using .format() on the string, filled in by each of the dictionaries in the list.
Here's my code: Please help!
dicts = [
{'name': 'Michelangelo',
'food': 'PIZZA'},
{'name': 'Garfield',
'food': 'lasanga'},
{'name': 'Walter',
'food': 'pancakes'},
{'name': 'Galactus',
'food': 'worlds'}
]
string = "Hi, I'm {name} and I love to eat {food}!"
def string_factory(dicts, string):
strings = []
for items in dicts:
string.format(**dicts)
return strings
print(string_factory(dicts, string))
6 Answers
Juan Martin
14,335 PointsHello my friend!
Here you can see 2 possible ways of doing it:
First:
def string_factory(dictionary, strings):
string_list = []
for i in range(len(dictionary)):
string_list.append(strings.format(**dictionary[i]))
return string_list
Second:
def string_factory(dictionary, strings):
string_list = []
for element in dictionary:
string_list.append(strings.format(**element))
return string_list
Hope this helps!
Have an awesome night :)
Spencer Johnson
19,708 Pointsthis worked for me:
def string_factory(dicts, string):
formatted = []
for data in dicts:
new_dict = data
formatted.append(string.format(**new_dict))
return formatted
print(string_factory(dicts, string))
Maxim Andreev
24,529 PointsCan someone dumb down '**' please, I understand how to use **kwargs, and *args for functions but how is the double asterick being used in this case?
beven nyamande
9,575 Pointsdouble asterisks are for unpacking items in a dictionary
yanni jain
693 Pointsdicts = [ {'name': 'Michelangelo', 'food': 'PIZZA'}, {'name': 'Garfield', 'food': 'lasanga'}, {'name': 'Walter', 'food': 'pancakes'}, {'name': 'Galactus', 'food': 'worlds'} ]
string = "Hi, I'm {name} and I love to eat {food}!" def string_factory(str,dict): new_list= [ string.format(dicts[0]), string.format(dicts[1]), string.format(dicts[2]), string.format(dicts[3]) ]
return new_list
i dont know where i am wrong it is giving an iteration error in ( new_list=[ )
yanni jain
693 Pointsplease reply and correct me!!
Daniel Muchiri
15,407 PointsThis worked for me:
def string_factory(dicts, string):
string_list = []
for a_dict in dicts:
string_list.append(string.format(**a_dict))
return string_list