Tony PitkinPro Student 1,950 Points
Formatting Dates in a simple way?
From the practice session:
Format dates in all the loans table in the UK format without the year. For example, April 1st is 01/04.
I came up with the following:
SELECT id, book_id, patron_id, STRFTIME("%m/%d", loaned_on) AS "loaned_on", STRFTIME("%m/%d", return_by) AS "return_by", STRFTIME("%m/%d", returned_on) AS "returned_by" FROM loans
My question: Is there a way to make the above more efficient?
Steven Parker203,238 Points
That's pretty close, unless you interpret the instructions to imply "return only the dates...", or to modify the dates in the table instead of just showing them.
Otherwise, the only issue is that they asked for the "UK format" which puts the day before the month.
Your format is a little off, it should be dd/mm. For a simpler interpretation of what they were asking here are only the dates without aliases.
SELECT STRFTIME("%d/%m", loaned_on), STRFTIME("%d/%m", return_by), STRFTIME("%d/%m", returned_on) FROM loans;
Anshul Laikar4,428 Points
This is what I came up with, in case they wanted us to actually replace the values given to us:
UPDATE loans SET loaned_on = STRFTIME("%d/%m", loaned_on), return_by = STRFTIME("%d/%m", return_by), returned_on = STRFTIME("%d/%m", returned_on);