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PHP

Posted by Steven Huntington
Steven Huntington
1,494 Points

Forms, Arrays, and Get Variables quiz problem

I'm on the last quiz in the PayPal section of the Simple PHP Application series, and this question is giving me issues:

What does the following block of code output?

<?php

$flavors = array();

$flavors[1] = "Cake Batter";

$flavors[2] = "Cookie Dough";

$x = 2;

if ($flavors[$x] != "Cookie Dough") {

echo "A";

} else {

echo "B";

}

?>

Option A: Page will display "B"

Option B: Page will display "A"

I read this to mean:

"if x doesn't equal Cookie Dough, echo A. Otherwise echo B"

and so I picked that the code would display "A" on the page, but that isn't the correct answer. I went back and looked again and my guess is that the $x variable isn't part of $flavors so the "if" statement is not true and displays the "else" value.

Can anyone clarify if this is the right explanation?

1 Answer

Carl Foote
Carl Foote
Courses Plus Student 8,129 Points 
$flavors[2] = "Cookie Dough";
$x=2;
$flavors[$x] = "Cookie Dough";

$x is 2 and $flavors[2] is Cookie Dough. I think the NOT was throwing you off. If it is NOT Cookie Dough then it is A, but it is so it is B.

Hope that makes sense,

Steven Huntington
Steven Huntington
1,494 Points

Ahh okay I had no idea that the value of a separate function could be applied inside another like that. I thought that when the "if" statement checked for the key it was checking for a key of "x" or a key of just "$x" (not associated with the $x variable), and not inferring to check for the value of the $x variable. Thanks for clearing that up.